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Answer by Bob D for How does a reversible Carnot cycle transform heat to work?
A quantity of heat $Q_H$ is absorbed at the high temperature $T_H$ andheat $Q_a$ remaining is rejected at the low temperature $T_a$.It is not an amount of heat $Q_a$"remaining". You should not think...
View ArticleHow does a reversible Carnot cycle transform heat to work?
To make clearer what I am asking let me introduce a new terminology to avoid any misunderstandings. Let the heat flow, which is rate, between a reservoir and an engine be denoted by $\mathfrak J$ and...
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